((60x^2)+33x-9)=0

Solution for ((60x^2)+33x-9)=0 equation:

((60x^2)+33x-9)=0

We get rid of parentheses

60x^2+33x-9=0

a = 60; b = 33; c = -9;
Δ = b2-4ac
Δ = 332-4·60·(-9)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3249}=57$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-57}{2*60}=\frac{-90}{120}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+57}{2*60}=\frac{24}{120}
=1/5
$